Question

# Match the compounds/ions in Column I with their properties/reactions in Column II ColumnIColumnII1.  Benzaldehydep. gives precipitate with 2,4-dinitrophenylhydrazine 2. Propyneq. gives precipitate with AgNO33. CN−r. is a nucleophile4. I−s. is involved in cyanohydrin formation

A

1. - p, q, r, s; 2 - q, r, s; 3 - r, s; 4 - r

B

1. - p, q, s; 2 - q,r; 3 - q, r, s; 4 - q, r

C

1. - p, q; 2 - q; 3 - r, s; 4 - r

D

1. - p, r, s; 2 - q, r; 3 - q, r, s; 4 - r

Solution

## The correct option is C 1. - p, q, s; 2 - q,r; 3 - q, r, s; 4 - q, r Carbonyls like aldehydes and ketones do form a yellow-orange precipitate with DNP. So it is no surprise that benzaldehyde - an aldehyde - gives a precipitate with 2,4-dinitrophenylhydrazine. Also, as an aldehyde, it can sure form a cyanohydrin with CN−. Benzaldehyde gives positive  Tollen's test. Propyne does not react with 2,4-DNPH or 2,4-dinitrophenylhydrazine. But it does decolourize bromine water or add to bromine (which is an excellent electrophile). Hence, we can make a case for propyne to be a nucleophile. Propyne does give a white precipitate  with AgNO3. It is not involved in cyanohydrin formation. CN− gives a precipitate with AgNO3. It is also a nucleophile; Further, it can form a cyanohydrin with carbonyls. I− gives a precipitate with AgNO3. It is also a nucleophile; Unlike CN−, iodide does not form a cyanohydrin with carbonyls. Chemistry

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