The correct option is
C C→Q,RIn case
(A)
Due to
I1,
→B at
P, from right-hand thumb rule, is upward and due to
I2 is out of the plane.
So, magnetic fields at point
P due to wires
1 and
2 are perpendicular to each other.
Also,
I1⊥I2. So, wires
1 and
2 do not exert any force on each other.
∴A→R,Q
In case
(B)
Similarly, as above,
→B at
P, due to
I1
is toward left and due to
I2 is into the plane.
So, magnetic fields at point
P due to wires
1 and
2 are perpendicular to each other.
Also,
I1⊥I2. So, wires
1 and
2 do not exert any force on each other.
∴B→R,Q
In case
(C)
→B at
P, due to
I1
is toward right and due to
I2 is out of the plane.
So, magnetic fields at point
P due to wires
1 and
2 are perpendicular to each other.
Also,
I1⊥I2. So, wires
1 and
2 do not exert any force on each other.
∴C→R,Q
In case
(D)
→B at
P, due to
I1 and
I2 is out of the plane.
So, magnetic fields at point
P due to wires
1 and
2 are in the same direction.
Also,
I1⊥I2. So, wires
1 and
2 do not exert any force on each other.
∴D→S,Q
Hence, option
(C) is correct.