Match the following- array - c - c -2- -tan 90 - circ - A - b lllaline3- -90- lcirc - A -space - c - cosAlspacelspacelspacelllhline lendarray A- 1-c - 2-b - 3-aB- 1- a - 2- b - 3 - cC- 1- a - 2- c - 3- bD- 1- b - 2- c - 3- a

The correct option is A 1 c; 2 b; 3 a sin A = BC/AC = cos(90^∘ A) cos A= AB/AC = sin(90^∘ A) tan A= BC/AB= cot(90^∘ A) cosec A= AC/BC= sec(90^∘ A) ...

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Standard X

Mathematics

Standard Values of Trigonometric Ratios

Match the fol...

Question

Match the following:

$\begin{matrix} 1. s i n (90^{\circ} - A) & a) c o s e c A 2. t a n (90^{\circ} - A) & b) c o t A 3. s e c (90^{\circ} - A) & c) c o s A \end{matrix}$

1- c; 2 - b; 3 - a

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1 - a; 2 - b; 3 - c

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1 - a; 2 - c; 3 - b

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1 - b; 2 - c;3 - a

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Solution

The correct option is A
1- c; 2 - b; 3 - a

$s i n A = \frac{B C}{A C} = c o s (90^{\circ} - A)$

$c o s A = \frac{A B}{A C} = s i n (90^{\circ} - A)$

$t a n A = \frac{B C}{A B} = c o t (90^{\circ} - A)$

$c o s e c A = \frac{A C}{B C} = s e c (90^{\circ} - A)$

$s e c A = \frac{A C}{A B} = c o s e c (90^{\circ} - A)$

$c o t A = \frac{A B}{B C} = t a n (90^{\circ} - A)$

Thus,

$s e c A = c o s e c (90^{\circ} - A)$

Suggest Corrections

Similar questions

Match the following:

$\begin{matrix} 1. s i n (90^{\circ} - A) & a) c o s e c A 2. t a n (90^{\circ} - A) & b) c o t A 3. s e c (90^{\circ} - A) & c) c o s A \end{matrix}$

Match the following:

$\begin{matrix} 1. s i n (90^{\circ} - A) & a) c o s e c A 2. t a n (90^{\circ} - A) & b) c o t A 3. s e c (90^{\circ} - A) & c) c o s A \end{matrix}$

Match the following:

$\begin{matrix} 1. s i n (90^{\circ} - A) & a) c o s e c A 2. t a n (90^{\circ} - A) & b) c o t A 3. s e c (90^{\circ} - A) & c) c o s A \end{matrix}$

Match the following:

$\begin{matrix} 1. s i n (90^{\circ} - A) & a) c o s e c A 2. t a n (90^{\circ} - A) & b) c o t A 3. s e c (90^{\circ} - A) & c) c o s A \end{matrix}$

Match the following:

$\begin{matrix} 1. c o s (90^{\circ} - A) & a) s e c A 2. c o t (90^{\circ} - A) & b) t a n A 3. c o s e c (90^{\circ} - A) & c) s i n A \end{matrix}$

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Match the following: 1. sin(90∘−A) a) cosecA2. tan(90∘−A)b) cotA 3. sec(90∘−A) c) cosA

The correct option is A 1- c; 2 - b; 3 - a sinA=BCAC=cos(90∘−A) cosA=ABAC=sin(90∘−A) tanA=BCAB=cot(90∘−A) cosecA=ACBC=sec(90∘−A) secA=ACAB=cosec(90∘−A) cotA=ABBC=tan(90∘−A) Thus, secA=cosec(90∘−A)

Match the following:

$\begin{matrix} 1. s i n (90^{\circ} - A) & a) c o s e c A 2. t a n (90^{\circ} - A) & b) c o t A 3. s e c (90^{\circ} - A) & c) c o s A \end{matrix}$