Question

Match the following
$\begin{array}{cc}ListI& ListII\\ A.\text{Reversible isothermal expansion}& \left(p\right)w=-R{P}_{ext}\frac{[T_2{P}_1-T_1{P}_2]}{P_1{P}_2}\\ B.\text{Irreversible isothermal expansion}& \left(q\right)w=\frac{R}{\gamma -1}[T_2-T_1]\\ C.\text{Reversible adiabatic expansion}& \left(r\right)w=-P_{ext}(V_2-V_1)\\ D.\text{Irreversible adiabatic expansion}& \left(s\right)w=-2.303nRTlo{g}_{10}{V}_2/V_1\end{array}$

• A. A - (s), B - (r). C-(q), D - (p)
• B. A - (s), B - (r). C-(p), D - (q)
• C. A - (r), B - (s). C-(q), D - (p)
• D. A - (p), B - (r). C-(q), D - (s)

Answer 1

The correct option is A A - (s), B - (r). C-(q), D - (p)

(a) For reversible isothermal expansion :
$w=-2.303nRTlo{g}_{10}{V}_2/V_1$

(b) For irreversible isothermal expansion :
$w=-P_{ext}(V_2-V_1)$

(c) For reversible adiabatic expansion :
$w=\Delta U=\frac{R}{\gamma -1}[T_2-T_1]$

(d) For irreversible adiabatic expansion :
$w=-P_{ext}\Delta V=-R{P}_{ext}\frac{[T_2{P}_1-T_1{P}_2]}{P_1{P}_2}$