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Question

Match the following:

(i) 425 × 136 = 425 × (6 + 30 + 100)

(a) Commutativity under multiplication

(ii) 2 × 49 × 50 = 2 × 50 × 49

(b) Commutativity under addition

(iii) 80 + 2005 + 20 = 80 + 20 + 2005

(c) Distributivity of multiplication over addition

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Solution

(i) 425 × 136 = 425 × (6 + 30 + 100) [Distributivity of multiplication over addition]

Hence, (c)

(ii) 2 × 49 × 50 = 2 × 50 × 49 [Commutativity under multiplication]

Hence, (a)

(iii) 80 + 2005 + 20 = 80 + 20 + 2005 [Commutativity under addition]

Hence, (b)


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