1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Match the following solid objects with the expressions of their volume.

A
2πr12h1+πr22h2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
πr2h+23πr3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
πr2h13πr2h
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## Volume of this solid object = Volume of the cylinder - volume of the cone = πr2h−13πr2h ∴ Volume of this solid object = πr2h−13πr2h Volume of this solid object = Volume of the cylinder + Volume of hemisphere = πr2h+23πr3 ∴ Volume of this solid object = πr2h+23πr3 Volume of this solid object = Volume of two cylinders with radii r1 + Volume of cylinder with radius r2 = 2×πr12h1+πr22h2 = 2πr12h1+πr22h2 ∴ ​Volume of this solid object = 2πr12h1+πr22h2

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Volume of a Cylinder
MATHEMATICS
Watch in App
Explore more
Join BYJU'S Learning Program