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Question

MATCH THE FOLLOWING
Hyperbola Length of latusrectum
A}x24y2=4 1. 1
B}25x216y2=400 2.12
C}2x2y24x4y20=0 3.9/2
D)9x216y2+72x32y16=0 4. 25/2
The correct match is

A
I II III IV
1 2 3 4
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B
1 4 2 3
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C
3 1 2 4
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D
2 3 4 1
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Solution

The correct option is A 1 4 2 3
(A) x24y2=1

LR=2b2a

=22

=1

(B)x216y225=1

b=5,a=4

LR=2.254

=252

(C) 2(x1)2(y2)2=18

(x1)29(y2)218=1

b2=18,a=3

LR=2×183

=12

(D) (x+4)216(y+1)29=1

b2=9

a=4

LR=2×94

=92

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