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Question

Match the polynomials with their respective factors.
  1. x1
  2. x3
  3. x5
  4. x7


Solution

The correct option is
According to the factor theorem, if (xa) is a factor of a polynomial f(x), then f(a) = 0.

For  f(x)=x23x+2
f(1)=123× 1+2=0.
Hence, (x1) is the factor of  x23x+2.

For  f(x)=x27x+12
f(3)=327× 3+12=0.
Hence, (x3) is the factor of  x27x+12.

For  f(x)=x211x+30
 f(5)=5211× 5+30=0.
Hence, (x5) is the factor of  x211x+30.

For  f(x)=x215x+56
f(7)=7215× 7+56=0.
Hence, (x7) is the factor of  x215x+56.

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