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Question

Match the two columns.
ColumnIColumnII(A)    Total surface area of cylinder is(p)    Its total surface areabase area(B)    Curved surface area of hemisphere(q)    Half of the circumference of Base×height2+base2(C)    Total surface area of a cone is(2×base area)+ (circumference of circle base×height)(D)    Curved surface area of a cone is(s)    area of base×(slant height+base radius)radius of circular base
Choose the correct option:


A
(A)q; (B)r; (C)s; (D)p
loader
B
(A)r; (B)p; (C)s; (D)q
loader
C
(A)p; (B)r; (C)q; (D)s
loader
D
(A)s; (B)q; (C)p; (D)r
loader

Solution

The correct option is A (A)r; (B)p; (C)s; (D)q
(A) TSA of cylinder =2πr2+2πrh
=2πr2+2πrh
2×base area+circumference of base×height
(B) CSA of hemisphere =2πr2
=3πr2πr2
= TSA of hemisphere – base area
(C) TSA of cone =πr(r+l)=πr2(r+l)r
=area of base×(radius+height)radius
(D) CSA of cone =πrl
=12×2πr×h2+r2    [l2=h2+r2]
=12 of circumference×height2+base2
option (b) is correct.

Mathematics

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