Question

# Match the two columns. Column−IColumn−II(A)    Total surface area of cylinder is(p)    Its total surface area−base area(B)    Curved surface area of hemisphere(q)    Half of the circumference of Base×height2+base2(C)    Total surface area of a cone is(2×base area)+ (circumference of circle base×height)(D)    Curved surface area of a cone is(s)    area of base×(slant height+base radius)radius of circular base Choose the correct option:

A
(A)q; (B)r; (C)s; (D)p
B
(A)r; (B)p; (C)s; (D)q
C
(A)p; (B)r; (C)q; (D)s
D
(A)s; (B)q; (C)p; (D)r

Solution

## The correct option is A (A)→r; (B)→p; (C)→s; (D)→q(A) TSA of cylinder =2πr2+2πrh =2πr2+2πrh 2×base area+circumference of base×height (B) CSA of hemisphere =2πr2 =3πr2−πr2 = TSA of hemisphere – base area (C) TSA of cone =πr(r+l)=πr2(r+l)r =area of base×(radius+height)radius (D) CSA of cone =πrl =12×2πr×√h2+r2    [∵l2=h2+r2] =12 of circumference×√height2+base2 ∴ option (b) is correct.Mathematics

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