Match the two columns - amp- Column-I amp- Column-II- amp-A-The -class- mark- of -the -class- interval amp- -p-13- amp- 145-150-is amp- amp-B-In -a -frequency -distribution- -the- mid - value- of- a amp- -q-110- amp- class -is -10 -and -width- of- each- class -is- 6- -The- upper amp- amp- limit -of -the- class- is amp- amp-C-The -mean- of- eight -numbers- is- 40- If -one amp- -r-22-5 - 27-5- amp-number- is -excluded- their -mean- becomes- 30- amp- amp- The- excluded -number- is amp- amp- -D-The- class -marks- of- a- frequency -distribution -are amp- -s-147-5- amp- 15- 20- 25- 30- - The- class- corresponding- to- the- class amp- amp- mark- 25 -is amp- - Choose the correct option- -A-p- B-s- C-q- D-rA-r- B-p- C-q- D-sA-s- B-p- C-r- D-qA-s- B-p- C-q- D-r

The correct option is D A s; B p; C q; D r(A) → s; (B) → p; (C) → q; (D) → r (A) Classmark =145+150/2=295/2=147.5. (B) Let the upper limit = x Lower limit = ...

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Standard X

Mathematics

Frequency Polygon

Match the two...

Question

Match the two columns
$\begin{matrix} C o l u m n - I & C o l u m n - I I (A) T h e c l a s s m a r k o f t h e c l a s s i n t e r v a l & (p) 13 145 - 150 i s (B) I n a f r e q u e n c y d i s t r i b u t i o n, t h e m i d - v a l u e o f a & (q) 110 c l a s s i s 10 a n d w i d t h o f e a c h c l a s s i s 6. T h e u p p e r l i m i t o f t h e c l a s s i s (C) T h e m e a n o f e i g h t n u m b e r s i s 40. I f o n e & (r) 22.5 - 27.5 n u m b e r i s e x c l u d e d, t h e i r m e a n b e c o m e s 30. T h e e x c l u d e d n u m b e r i s (D) T h e c l a s s m a r k s o f a f r e q u e n c y d i s t r i b u t i o n a r e & (s) 147.5 15, 20, 25, 30, \dots \dots T h e c l a s s c o r r e s p o n d i n g t o t h e c l a s s m a r k 25 i s \end{matrix}$

Choose the correct option:

A-p; B-s; C-q; D-r

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A-r; B-p; C-q; D-s

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A-s; B-p; C-r; D-q

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A-s; B-p; C-q; D-r

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Solution

The correct option is D A-s; B-p; C-q; D-r
$(A) \to s; (B) \to p; (C) \to q; (D) \to r$

(A) Classmark
$= \frac{145 + 150}{2} = \frac{295}{2} = 147.5$ .

(B) Let the upper limit = x
Lower limit = y
$∴ x - y = 6$ and $\frac{x + y}{2} = 10 \Rightarrow x + y = 20$
On solving both the equations, we get x = 13 and y = 7

(C) Sum of the 8 observation $= 40 \times 8 = 320$
Sum of the 7 observation $= 30 \times 7 = 210$
Excluded observation is 320 - 210 = 110

(D) Class width = 20 - 15 = 5
Class mark = 25
$∴$ Required class,
$(25 - \frac{5}{2}) - (25 + \frac{5}{2}) \Rightarrow 22.5 - 27.5$

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Similar questions

Q. The class marks of a frequency distribution are 15, 20, 25, 30, .. . The class corresponding to the class marks 20 is
(a) 12.5−17.5
(b) 17.5−22.5
(c) 18.5−21.5
(d) 19.5−20.5

Choose the correct answer in each of the following questions:
The class marks of a frequency distribution are 15, 20, 25, 30, .... The class corresponding to the class mark 20 is
(a) 12.5-17.5
(b) 17.5-22.5
(c) 18.5-21.5
(d) 19.5-20.5

Q. The width of each of the five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is
(a) 45
(b) 25
(c) 35
(d) 40

Choose the correct answer in each of the following questions:
The width of each of the five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is
(a) 45
(b) 25
(c) 35
(d) 40

Q. Match the two columns

\begin{matrix} C o l u m n - I & C o l u m n - I I (A) T h e c l a s s m a r k o f t h e c l a s s i n t e r v a l & (p) 13 145 - 150 i s (B) I n a f r e q u e n c y d i s t r i b u t i o n, t h e m i d - v a l u e o f a & (q) 110 c l a s s i s 10 a n d w i d t h o f e a c h c l a s s i s 6. T h e u p p e r l i m i t o f t h e c l a s s i s (C) T h e m e a n o f e i g h t n u m b e r s i s 40. I f o n e & (r) 22.5 - 27.5 n u m b e r i s e x c l u d e d, t h e i r m e a n b e c o m e s 30. T h e e x c l u d e d n u m b e r i s (D) T h e c l a s s m a r k s o f a f r e q u e n c y d i s t r i b u t i o n a r e & (s) 147.5 15, 20, 25, 30, \dots \dots T h e c l a s s c o r r e s p o n d i n g t o t h e c l a s s m a r k 25 i s \end{matrix}

Choose the correct option:

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