Maximum number of electrons that can occupy s, p, d and f sub shells respectively are:

4, 5, 6, 7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2, 6, 10, 14

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2, 4, 8, 16

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1, 2, 3, 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 2, 6, 10, 14
The maximum number of electrons in a subshell can be given by a formula $2 \times (2l + 1)$ .
For s subshell, the value of l = 0
Hence, maximum number of electrons in s-subshell = $2 \times (2 \times 0 + 1)$
= 2

$\begin{matrix} S u b s h e l l & V a l u e o f l & M a x i m u m n u m b e r o f e l e c t r o n s i n t h e s u b s h e l l (2 \times (2 l + 1)) s & 0 & 2 \times (2 \times (0) + 1) = 2 p & 1 & 2 \times (2 \times (1) + 1) = 6 d & 2 & 2 \times (2 \times (2) + 1) = 10 f & 3 & 2 \times (2 \times (3) + 1) = 14 \end{matrix}$

Suggest Corrections

Similar questions

Sub shells	Number of orbitals $(2 l + 1)$	Maximum number of electrons
$s (l = 0)$	$1$	$2$
$p (l = 1)$	$3$	$6$
$d (l = 2)$	$5$	$10$
f(l = 3)$	$7$	$14$

Write which sub shell has maximum number of electrons?

The electronic configuration of gadolinium (Atomic number 64) is
(a) $[X e] 4 f^{3} 5 d^{5} 6 s^{2}$
(b) $[X e] 4 f^{7} 5 d^{2} 6 s^{1}$
(c) $[X e] 4 f^{7} 5 d^{1} 6 s^{2}$
(d) $[X e] 4 f^{8} 5 d^{6} 6 s^{2}$

Q. In the following number sequence how many 4's are there that are immediately preceded by 6 and immediately followed by 5?
3 4 2 6 5 4 3 6 4 5 9 8 6 4 5 3 8 7 4 6 8 2 1 7 6 4 5 8 6 4 5 9 7 4 5

Sub shells	Number of orbitals $(2 l + 1)$	Maximum number of electrons
$s (l = 0)$	$1$	$2$
$p (l = 1)$	$3$	$6$
$d (l = 2)$	$5$	$10$
$f (l = 3)$	$7$	$14$

Write the number of orbitals for

^{'} d^{'}

shell.

The maximum number of electrons that can occupy the shell K, L, M, N respectively are:

Join BYJU'S Learning Program