Mean of 100 items is 49. It was discovered that three items which should have been 60, 70, 80 were wrongly read as 40, 20, 50 respectively. Correct mean will be

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82 \frac{1}{2}

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Solution

The correct option is C 50
Sum of 100 items = $49 \times 100 = 4900$
Sum of items = 60 + 70 + 80 = 210
Sum of items replaced = 40 + 20 + 50 = 110
$∴$ New sum = 4900 – 110 + 210 = 5000
$∴$ Correct mean = $\frac{5000}{100} = 50$

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Mean of 100 items is 49. It was discovered that three items which should have been 60, 70, 80 were wrongly read as 40, 20, 50 respectively. Correct mean will be

The correct option is C 50Sum of 100 items = 49×100=4900 Sum of items = 60 + 70 + 80 = 210 Sum of items replaced = 40 + 20 + 50 = 110 ∴ New sum = 4900 – 110 + 210 = 5000 ∴ Correct mean = 5000100=50

The correct option is C 50
Sum of 100 items = $49 \times 100 = 4900$
Sum of items = 60 + 70 + 80 = 210
Sum of items replaced = 40 + 20 + 50 = 110
$∴$ New sum = 4900 – 110 + 210 = 5000
$∴$ Correct mean = $\frac{5000}{100} = 50$