CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Minimum area of the triangle by any tangent to the ellipse x2a2+y2b2=1 with the coordinate axes is

A
a2+b22
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(a+b)22
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
ab
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
(ab)22
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B ab
Equation of tangent at (acosθ,bsinθ) is
xacosθ+ybsinθ=1
then, P=(acosθ,0);Q=(0,bsinθ)
Area of OPQ=12(acosθ)(bsinθ)=ab|sin2θ|
Area =ab

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rate of Change
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon