Question

Minimum numbers of $8\mu F$ and 250 V capacitors are used to make a combination of $16\mu F$ and 1000 V are:

• A. 4
• B. 32
• C. 8
• D. 3

Answer 1

The correct option is B 32

To create 1000 Y, we need to combine 4 capacitors

in series. Total capacity becomes $\frac{8\mu F}{4}=2\mu F$.In order to obtain capacity of $16\mu F$, 8-rows of this combination will be needed in parallel.

Total capacity $=2\mu F\times 8=16\mu F$

Total number of capacitor $=4\times 8=32$