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Question

Minimum value of 5sin2θ+4cos2θ is


A

1

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B

2

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C

3

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D

4

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Solution

The correct option is D

4


Let f(θ) = 5sin2θ+4cos2θ = 4+sin2θ

f(θ) 4 + 0 (sin2θ0)

∴ The minimum value of f(θ) is 4.


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