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Question

Minimum value of Z=x5y+20 under the given conditions 
xy0x+2y2x3,y4x,y0
is
  1. 4
  2. 8
  3. 1
  4. 6


Solution

The correct option is A 4
First draw the feasible region 
xy=0x+2y=2x=3y=4


From the above figure, the corner points of the feasible region are 
Corner point Objective function Z=x5y+20
A(3,3) 8
B(3,2.5) 10.5
C(6,4) 6
D(4,4) 4 minimum

Zminimum=4 at D(4,4)

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