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Acidic Nature vs Percentage S Characters

Mixture of on...

Question

Mixture of one mole each of ethene and propyne on reaction with $N a$ will form $H_{2}$ gas at S.T.P?

A

22.4 L

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B

11.2 L

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C

33.6 L

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D

44.8 L

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Solution

The correct option is B 11.2 L
Sodium reacts with propyne (ethene) and 2 mole of propyne is used to give one mole of hydrogen gas so one mole of propyne will give 0.5 mole of hydrogen (11.2 lit.). The reaction will be:
$C H_{2} = C H_{2} + 2 C H_{3} - C C H \to C H C - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C C H + H_{2}$

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