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Question

Modulus of (3+2i32i) is equal to

A
1
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B
12
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C
2
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D
2
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Solution

The correct option is A 1
On Rationalisation
3+2i32i×3+2i3+2i=9+4i2+12i94i2=94+12i9(4)=5+12i9+4=5+12i13

Now, we have to find
5+12i13=52+12213=1313=1

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