Molality (in mol/kg) of a solution in which 0.13 mole of solute is dissolved in 500 gm of water is:

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1.3

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2.6

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0.26

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Solution

The correct option is D
0.26

We know,
Molality (m) = $\frac{N o o f g r a m m o l e s o f s o l u t e}{M a s s o f s o l v e n t (k g)}$
Mass of solvent is given to be 500 gm
(water)
Gram moles of solute is 0.13
m=( 0.13X1000)/500 =0.13 X2=0.26

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