Question

# Molarity and molality of a solution of a liquid (mol wt=50) in aqueous solution is 9 and 10 respectively. What is the density of solution?

A
1 g/cc
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B
0.95 g/cc
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C
1.05 g/cc
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D
1.35 g/cc
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Solution

## The correct option is D 1.35 g/ccMolarity =Mass of soluteMolar mass of solute×1000Volume of solutionM=wm′×1000v⟹w=M×m′×v1000⟶(1)Molality =Mass of soluteMolar mass of solute×1000Mass of solventw=wm′×1000w′⟹w=m×m′×w′1000⟶(2)Mass of solution=Mass of solvent+Mass of solutew"=w+w′vd=w+w′w′=vd−w⟶(3)Putting value of w′ in equation (2) and on equate equation (1) and (2),we get,M×m′×v1000=m×m′×(vd−w)1000M×v=mvd−mwM×v=mvd−m(Mm′v1000)M=m(d−m′M100)OR,d=M(1m+m′1000)density=molarity(1molality+molecular weight1000)d=9(110+501000)=1.35 g/cc

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