Moment of inertia of a thin uniform rod rotating about the perpendicular axis passing through its centre is I . If the same rod is bent into a ring and its moment of inertia about its diameter is I ; then the ratio I/l is

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Q. Moment of Inertia of a thin uniform rod rotating about the perpendicular axis passing through its centre is

I

. If the same rod is bent into a ring and its moment of inertia about its diameter is

I^{'}

, then the ratio

\frac{I}{I^{'}}

Moment of Inertia of a thin uniform rod rotating about the perpendicular axis passing through its centre is I. If the same rod is bent into a ring and its moment of inertia about its diameter is I’, then the ratio $\frac{I}{I^{'}}$ is

I

is moment of inertia of a circular ring about an axis passing through its diameter. This ring is cut then unfolded into a straight rod. The moment of inertia of rod about an axis perpendicular to its length and passing through its end is :

Q. If

I_{1}

is the moment of inertia of a thin rod about an axis perpendicular to its length and passing through its centre of mass, and

I_{2}

is the moment of inertia (about central axis) of the ring formed by bending the rod, then

Q. If

I_{1}

the moment of inertia of a thin rod about an axis perpendicular to its length and passing through its centre of mass and

I_{2}

the moment of inertia of the ring formed by the same rod about an axis passing through the centre of mass of the ring and perpendicular to the planet of the ring. Then find the ratio

\frac{I_{1}}{I_{2}}

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