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Question

Moment of inertia. of a uniform rod of length Land mass $$M,$$ about an axis passing through $$L/ 4$$ from one end and perpendicular to its length is


A
736ML2
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B
748ML2
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C
1148ML2
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D
ML212
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Solution

The correct option is B $$\displaystyle \frac{7}{48}ML^{2}$$
$$\displaystyle I=\frac{ML^{2}}{12}+M\left( \frac{L}{4}\right) ^{2}$$
$$\displaystyle =\frac{7}{48}ML^{2}$$

Physics

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