Question

Moment of inertia. of a uniform rod of length Land mass $M,$ about an axis passing through $L/4$ from one end and perpendicular to its length is

• A. $\frac{7}{36}M{L}^2$
• B. $\frac{7}{48}M{L}^2$
• C. $\frac{11}{48}M{L}^2$
• D. $\frac{M{L}^2}{12}$

Answer 1

The correct option is B $\frac{7}{48}M{L}^2$

$I=\frac{M{L}^2}{12}+M{\left(\frac{L}{4}\right)}^2$
$=\frac{7}{48}M{L}^2$