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If $x + \frac{x}{2} + \frac{x}{6} + \frac{x}{12} + \frac{x}{20} + . . . + \frac{x}{380} = 39,$ then x equals

यदि $x + \frac{x}{2} + \frac{x}{6} + \frac{x}{12} + \frac{x}{20} + . . . + \frac{x}{380} = 39,$ तब x बराबर है

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\sqrt{361}

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\sqrt{400}

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The correct option is D $\sqrt{400}$
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