mtan (-30)=ntan(+120),then prove that m+n/m-n =?

Open in App

Solution

Suggest Corrections

Similar questions

m tan (θ - 30^{\circ}) = n tan (θ + 120^{\circ})

cos 2 θ = \frac{m + n}{2 (m - n)}

m tan (θ - 30^{o}) = n tan (θ + 120^{o})

cos 2 θ = \frac{(m + n)}{2 (m - n)}

m t a n (θ - 30) = n t a n (θ = 120)

\frac{m + n}{m - n}

If tanA=ntanB and sinA=msinB ,prove that cos²A =m² -1/n² - 1

\sqrt{m} + \sqrt{n} - \sqrt{p} = 0,

(m + n - p)^{2} = 4 m n

Join BYJU'S Learning Program