Question

Multiply $26244$ by the smallest number so that the product is a perfect cube. What is that number? Also find the cube root of the product.

Answer 1

$\sqrt[3]{326244}=\sqrt[3]{32^2\times 3^8}=\sqrt[3]{32^2\times 3^2\times 3^6}=9\sqrt{2^2\times 3^2}$

If $6$ is a multiplied

$=9\sqrt[3]{32^3\times 3^3}=54$

$\therefore$ We need $6$ to be multiplied to the no. to make it a perfect cube.