Multiply: $(4 x^{4} - 3 x^{2} - 7 x + 8)$ by $(5 x^{2} - 2 x - 3)$
Answer: $20 x^{6} - 8 x^{5} - 27 x^{4} - 29 x^{3} + 63 x^{2} + 5 x - 24$

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A True
Multiplying term by term and then adding,
$(4 x^{4} - 3 x^{2} - 7 x + 8) \times (5 x^{2} - 2 x - 3)$
$= 4 x^{4} (5 x^{2} - 2 x - 3) - 3 x^{2} (5 x^{2} - 2 x - 3) - 7 x (5 x^{2} - 2 x - 3) + 8 (5 x^{2} - 2 x - 3)$
$= 20 x^{6} - 8 x^{5} - 12 x^{4} - 15 x^{4} + 6 x^{3} + 9 x^{2} - 35 x^{3} + 14 x^{2} + 21 x + 40 x^{2} - 16 x - 24$
$= 20 x^{6} - 8 x^{5} - 27 x^{4} - 29 x^{3} + 63 x^{2} + 5 x - 24$

Suggest Corrections

Similar questions

(2 x^{3} - 3 x^{2} + 2 x - 3)

(3 x^{2} - 4 x + 1)

6 x^{5} - 17 x^{4} + 20 x^{3} - 20 x^{2} + 14 x - 3

({5 x}^{2} - 7 x + 4)

(2 x - {5 x}^{3} + 1)

({3 x}^{2} - 1 + 5 x)

(x^{2} - 5 x + 2)

(3 x^{2} + 2 x - 5)

Join BYJU'S Learning Program

Select...