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Question

# Intensity of sunlight is observed as 0.092 Wm−2 at a point in free space. What will be the peak value of magnetic field at that point ? (ε0=8.85×10−12 C2N−1m−2)

A
8.31 T
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B
5.88 T
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C
2.77×108 T
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D
1.96×108 T
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Solution

## The correct option is C 2.77×10−8 TIf B0 is the peak value of magnetic field and c is the velocity of light in free space, then the intensity is given by, I=B20c2μ0 and 1μ0=ε0c2 ⇒I=B202ε0c3 ⇒B0=√2Iε0c3 ⇒B0=√2×0.092(8.85×10−12)(3×108)3 ⇒B0=2.77×10−8 T Hence, (A) is the correct answer.

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