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Question

nC012nC1+13nC2...........+(1)nnCnn+1


  1. 1/n

  2. n


Solution

The correct option is B


Trick : Put n = 1, 2

At n = 1, 1C0121C1 = 1 -  1212

At n =2,  2C0122C1132C2 = 1 - 1 +  1313

which is given by option (c).

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