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Question

n cells, each of emf e and internal resistance r are joined in series to form a row. m such rows are connected in parallel to form a battery of N=mn cells. This battery is connected to an external resistance R
What is the emf of this battery and how much is its internal resistance?

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Solution

emf=ne

Internal resistance of 1 row=nr

1r=1nr+1nr+.....m times

1r=mnr

r=nrm

624988_597052_ans_7193a61db220412dbb5121b288a3f8de.png

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