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Question

n-propyl bromide reacts with ethanolic KOH to form :


A
propane
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B
propene
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C
propyne
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D
propanol
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Solution

The correct option is B propene
n-propyl bromide reacts with ethanolic KOH to form propene.

$$CH_3-CH_2-CH_2-Br \xrightarrow{Ethanolic \ KOH} CH_3-CH=CH_2+KBr + H_2O$$


Chemistry

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