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Hardness of Water and Treatment

Na2CO3 is wid...

Question

$N a_{2} C O_{3}$ is widely used in softening of hard water. If 1 L of hard water required $0.0106 g$ of $N a_{2} C O_{3}$ , The hardness in ppm (parts per million i.e., $10^{6}$ ml) of $C a C O_{3}$ is:

0.01

ppm

C a C O_{3}

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0.10

ppm

C a C O_{3}

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1.00

ppm

C a C O_{3}

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10.00

ppm

C a C O_{3}

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Solution

The correct option is C $10.00$ ppm $C a C O_{3}$
Hardness (in ppm)= $\frac{W e i g h t o f N a_{2} C O_{3} r e q u i r e d (i n m g)}{V o l u m e o f H a r d w a t e r (i n L)}$
= $\frac{0.0106 \times 10^{3}}{1}$
= $10.6$
$\approx 10 p p m$
$∴$ Hardness (in ppm)= $10$ ppm $C a C O_{3}$

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