Question

$NaH{CO}_3$ and $KH{CO}_3$ belong to the same category of compounds. Which of the following statement(s) is/are false?

• A. $NaH{CO}_3$ is less soluble in water than $KH{CO}_3$
• B. In solid-state, $NaH{CO}_3$ has infinite chain of hydrogen bonding whereas $KH{CO}_3$ forms dimeric hydrogen bonding
• C. Both can exist independently in solid state
• D. $K_2{CO}_3$ can be prepared by Solvay process similar to ${Na}_2{CO}_3$

Answer 1

Answer: (C), (D)

The correct options are
C Both can exist independently in solid state
D $K_2{CO}_3$ can be prepared by Solvay process similar to ${Na}_2{CO}_3$

$\begin{array}{c}\text{- Both}{NaHCO}_3\text{and}{KHCO}_3\text{does not exist independently}\\ \text{and exist as hydrogen bonded in solid}\\ \text{state.}\end{array}$

$K_{2}C{O}_3$ can not be prepared by solvay's process

like ${Na}_{2}CO3$ because ${NaHCO}_3$

formed between

the process is less soluble than $KHC{O}_3$

option $\left(C\right)$ and $\left(D\right)$ are correct.