Question

# ${\mathrm{Na}}^{+}$ has completely filled $\mathrm{K}$ and $\mathrm{L}$ shells. Explain.

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Solution

## Electronic configuration:-In quantum chemistry, the electronic configuration is actually the distribution of the electrons in the orbitals of an atom.Sodium is basically a member of the alkali metal family.A positive ion or cation is generally formed by the losing of electrons.Sodium atom ($\mathrm{Na}$) has atomic number = 11So, the number of protons and electrons Sodium atom ($\mathrm{Na}$) has = 11 each.So, the electronic configuration of $\mathrm{Na}$ atom in the different shells (K, L, M) = 2, 8, 1.So, if Sodium atom loses 1 electron to become (${\mathrm{Na}}^{+}$), then the electronic configuration would be (K, L) = 2, 8.Hence, K and L shells are completely filled, which is (2, 8) and this is a electronic configuration.

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