Neha dropped a stone into a very deep well. She heard the sound only after 6.53 seconds after she dropped the stone. Find the depth of the river if the acceleration due to gravity=10m/s² and the velocity of the sound is 340m/s

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Solution

s=ut+1/2gt^2

here initial velocity u=0

so s=1/2gt^2
g=10 t=6.53
therefore distance s=1/2106.536.53
=56.53*6.53
=213.2m

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In the above question how to solve equation √D/5 + D/340 = 6.53

Tinku dropped a stone into a very deep well. He hears the sound $6.53 s$ after he dropped the stone. Find the depth of the well. Take acceleration due to gravity, $g = 10 m s^{- 2}$ and $v_{s o u n d} = 340 m s^{- 1}$ .

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Neha dropped a stone into a very deep well. She heard the sound only after 6.53 seconds after she dropped the stone. Find the depth of the river if the acceleration due to gravity=10m/s² and the velocity of the sound is 340m/s ​​​​​

s=ut+1/2gt^2 here initial velocity u=0 so s=1/2gt^2 g=10 t=6.53 therefore distance s=1/2*10*6.53*6.53 =5*6.53*6.53 =213.2m

Neha dropped a stone into a very deep well. She heard the sound only after 6.53 seconds after she dropped the stone. Find the depth of the river if the acceleration due to gravity=10m/s² and the velocity of the sound is 340m/s

s=ut+1/2gt^2

here initial velocity u=0

so s=1/2gt^2
g=10 t=6.53
therefore distance s=1/2106.536.53
=56.53*6.53
=213.2m