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Question

Neon has two isotopes, $$^{20}Ne$$ and $$^{22}Ne$$. If atomic weight of Neon is 20.2, then the ratio of the relative abundances of the isotopes is:


A
1 : 9
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B
9 : 1
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C
1 : 7
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D
7: 1
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Solution

The correct option is A 9 : 1
Let, the $$\mathrm{w}\%$$ of  $$^{20}Ne=x$$
$$\mathrm{w} \%$$ of  $$^{22}Ne=100-x$$
$$20.2=\displaystyle \displaystyle\frac{x\times 20+(100-x)\times 22}{100}$$
$$2020=20x+2200-22x$$
$$2x =2200-2020 =180$$
$$ x=90\%$$
$$\therefore $$   $$\mathrm{w}\%$$ of $$^{20}Ne=90\%$$
    $$\mathrm{w}\%$$ of $$^{22}Ne=10\%$$

The ratio of the relative abundances of the isotopes is:
       $$\therefore $$  $$^{20}Ne $$    :     $$^{22}Ne$$

              $$= 9:1$$

Hence, option B is correct.

Chemistry

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