Nisha swims in a 90 m long pool. She covers 180 m in one minute by swimming from one end to the other and back along the same straight path. Find the average velocity of Nisha.

0 m / s

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3 m / s

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6 m / s

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None of these

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Solution

The correct option is A $0 m / s$
Total displacement $= 0$
Time taken, $t = 1 m i n = 60 s e c$
Average velocity $(V_{a v}) = \frac{Total Displacement}{total time taken}$
$V_{a v} = \frac{0}{60} = 0 m / s$

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Why displacement is taken 0 here?

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Nisha swims in a 90 m long pool. She covers 180 m in one minute by swimming from one end to the other and back along the same straight path. Find the average velocity of Nisha.

The correct option is A 0 m/sTotal displacement =0Time taken, t=1 min=60secAverage velocity (Vav)=Total Displacementtotal time takenVav=060=0 m/s

The correct option is A $0 m / s$
Total displacement $= 0$
Time taken, $t = 1 m i n = 60 s e c$
Average velocity $(V_{a v}) = \frac{Total Displacement}{total time taken}$
$V_{a v} = \frac{0}{60} = 0 m / s$