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Question

Nitric oxide, NO, reacts with oxygen gas to form nitrogen dioxide, a dark brown gas.
What mass of nitrogen dioxide could be produced from 20.3 g of nitric oxide and 5.89 g of oxygen gas?

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Solution

2NO+O22NO2
Number of moles of NO in 20.3g=20.3g30=0.67 moles
Number of moles of O2 in 5.6g=5.632=0.175 moles
As 1 mole of O2 is reacting with 2 moles of NO
0.175 moles of O2 is reacting with 2×0.175 moles of NO=0.35 moles of NO .
Thus O2 is limiting agent.
Moles 2NO+O22NO2
at t=0 0.67 0.175 -
After reaction 0.670.35 - 0.35
Thus moles of NO2 produce= 0.35 as 1 mole of O2 give 2 moles of NO2.
Mass of NO2 produced= n × Molar mass
=0.35×46
mNO2=16.1g
Thus 16.1g of NO2 is produced.

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