wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Normality of 100V H2O2 is

A
8.9 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.89 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.78 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
17.86 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 17.86 N
10 V = 1.786 N
100 V = ?
100V×1.786N10V=17.86N

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Measurement of Significant Figures
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon