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Question

Note Take π=227, unless stated otherwise.
A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of ₹ 32 per 100 cm2.

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Solution

Inner radius of the bowl, r = 10.52 = 5.25 cm

∴ Inner curved surface area of the bowl = 2πr2=2×227×5.252 = 173.25 cm2

Rate of tin-plating = ₹ 32 per 100 cm2

∴ Cost of tin-plating the bowl on the inside

= Inner curved surface area of the bowl × Rate of tin-plating

=173.25×32100

= ₹ 55.44

Thus, the cost of tin-plating the bowl on the inside is ₹ 55.44.

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