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First Law of Thermodynamics

ntA closed sy...

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ntA closed system undergoes change of state by process 1-->n nt2 for which Q12=10J and W12=-5J .the system is now returned to it's initial state by a different path 2--,> 1 for which Q21 is -3 J the work done by the gas in the process 2--> 1n

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Q. A closed system undergoes a change of state by process

1 \to 2

Q_{12} = 10 J

W_{12} = - 5 J

. The system is now returned to its initial state by a different path

2 \to 1

Q_{21}

- 3 J

. The work done by the gas in the process

2 \to 1

Q. A gas undergoes change from state A to state B. In this process, the heat absorbed and work done by the gas is 5J and 8J, respectively. Now gas is brought back at A by another process during which 3J of heat is evolved. In this reverse process of B to A:

Q. The state of a mole of an ideal gas changed from state A(

2 p, v

) through four different processes and finally return to initial state A reversibly as shown below.

Calculate the total work done by the system and heat absorbed by the system in the cyclic process respectively.

Q. The state of a mole of an ideal gas changed from state A(

2 p, v

) through four different processes and finally return to initial state A reversibly as shown below.

Calculate the total work done by the system and heat absorbed by the system in the cyclic process respectively.

Q. A gas undergoes a change from state A to state B. In this process, the heat absorbed and work done by the gas is 5 J and 8 J, respectively. Now gas is brought back to A by another process during which 3 J of heat is evolved. In this reverse process of B to A:

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