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Standard X
Chemistry
Ionic Bond
ntA deuteron ...
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ntA deuteron and an alpha particle are placed in an electric field. The force acting on them are F1 and F2 and their acceleration are a1 and a2 respectively, thenn nt(1) F1 = F2n nt(2) F1 > F2n nt(3) a1 = a2n nt(4) a1 is not equal to a2n
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Q.
A deuteron and an
α
-particle are placed in an electric field. The forces acting on them are
F
1
and
F
2
, and their accelerations are
a
1
and
a
2
respectively.
Q.
Assertion :A deuteron and an
α
−
particle are placed in an electric field. If
F
1
and
F
2
be the forces acting on them and
a
1
and
a
2
be their accelerations respectively then,
a
1
=
a
2
. Reason: Forces will be same in electric field.
Q.
If
a
1
,
a
2
,
a
3
,
.
.
.
.
a
2
n
+
1
are in A.P. then
a
2
n
+
1
−
a
1
a
2
n
+
1
+
a
1
+
a
2
n
−
a
2
a
2
n
+
a
2
+
.
.
.
+
a
n
+
2
−
a
n
a
n
+
2
+
a
n
is equal to
Q.
If
a
r
>
0
,
r
ϵ
N
and
a
1
,
a
2
,
a
3
,...,
a
2
n
are in AP then
a
1
+
a
2
n
√
a
1
+
√
a
2
+
a
2
+
a
2
n
−
1
√
a
2
+
√
a
3
+
a
3
+
a
2
n
−
2
√
a
3
+
√
a
4
+
.
.
.
+
a
n
+
a
n
+
1
√
a
n
+
√
a
n
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is equal to
Q.
If
a
r
>
0
,
r
∈
N
and
a
1
,
a
2
,
a
3
,
.
.
.
,
a
2
n
are in A.P. then
a
1
+
a
2
n
√
a
1
+
√
a
2
+
a
2
+
a
2
n
−
1
√
a
2
+
√
a
3
+
a
3
+
a
2
n
−
2
√
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3
+
√
a
4
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.
.
.
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a
n
+
a
n
+
1
√
a
n
+
√
a
n
+
1
is equal to
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