ntFind the solubility product of a saturated solution of silver chromate in water at 298 K if emf of the cell Ag/Ag2CrO4 (saturated solution)//Ag+ (0.1 M) /Ag is 0.164 V at 298 K.n

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The solubility product of a saturated solution of $A g_{2} C r O_{4}$ in water at 298 K will be................., if the EMF of the cell:

A g | A g^{\oplus} (s a t A g_{2} C r O_{4} s o l) | | A g (0.1 M) | A g

0.164 V

at 298 K.

Q. Find the solubility product of a saturated solution of

A g_{2} C r O_{4}

in water at

298 K

if the emf of the cell

A g | A g^{+}

(satd.

A g_{2} C r O_{4} s o l n .) | | A g^{+} (0.1 M) | A g

0.164 V

298 K

At 298 K, the conductivity of a saturated solution of AgCl in water is $2.6 \times 10^{- 6} S c m^{- 1}$ . Its solubility product at 298 K (given : $λ^{\infty} (A g^{+}) = 63.0 S c m^{2} m o l^{- 1}, λ^{\infty} (C l^{-}) = 67.0 S c m^{2} m o l^{- 1})$