CameraIcon

SearchIcon

MyQuestionIcon

Special Latitudes

ntLet x be th...

Question

ntLet x be the latitude at a place and y be the dip of that place, then prove thatn nttan x = (tan y)/2n

Open in App

Solution

Suggest Corrections

thumbs-up

0

mid-banner-image

mid-banner-image

Similar questions

Q. At a place of latitude 5

^{o}

, the angle of dip is nearly

Q. A dip needle lies initially in the magnetic meridian when it shows an angle of

d i p θ

at a place. The dip circle is rotated through an angle

x

in the horizontal plane and then it shows an angle of

d i p θ^{'}

\frac{tan θ^{^{'}}}{tan θ}

Q. A dip needle lies initially in the magnetic meridian when it shows an angle of dip

θ

at a place. The dip circle is rotated through an angle

x

in the horizontal plane and then it shows an angle of dip

θ' .

\frac{tan θ'}{tan θ}

If horizontal and vertical components of the earth's magnetic field are equal at a certain place, then the angle of the dip at that place will be

Q. A dip needle lies initially in the magnetic meridian when it shows an angle of dip

θ

at a place. The dip circle is rotated through an angle

x

in the horizontal plane and then it shows an angle of dip

θ^{'}

\frac{tan θ^{'}}{tan θ}

View More

Join BYJU'S Learning Program

Select...

similar_icon

Related Videos

lock

Special Latitudes

GEOGRAPHY

Watch in App

explore_more_icon

Explore more

Special Latitudes

Standard VI Geography

Join BYJU'S Learning Program

Select...