CameraIcon

SearchIcon

MyQuestionIcon

Second Law of Motion

ntn ntQ. An o...

Question

ntn ntQ. An object is projected from ground with speed u at angle with horizontal. The radius of curvature of its trajectory at maximum height from the ground isn nt1) u2 sin2/gn nt2) u2 cos2/gn nt3) u2 sin2 /gn nt4) u2 sin2 /2gn

Open in App

Solution

Suggest Corrections

thumbs-up

0

mid-banner-image

mid-banner-image

Similar questions

Q. Assertion :Maximum possible height attained by a projectile is

\frac{u^{2}}{2 g}

, where u is initial velocity Reason: To attain maximum height, a particle is thrown vertically upwards at

θ = 90^{o}

H = \frac{u^{2}}{2 g} s i n^{2} θ \Rightarrow H_{m a x} = \frac{u^{2}}{2 g}

Q. When a body is projected with velocity

\to u

horizontally from a height

h

Column-I	Column-II
(a)	The speed of body at any time $t$ is	(p)	$\sqrt{\frac{2 g h}{u^{2}}}$
(b)	It will strike the ground after time $t$ equal to	(q)	$\sqrt{\frac{2 h}{g}}$
(c)	The path followed by the body is expressed as $y$ equal to	(r)	$- \frac{1}{2} g \frac{x^{2}}{u^{2}}$
(d)	The tangent of the angle $θ$ made by velocity vector striking the ground with horizontal is equal to	(s)	$\sqrt{u^{2} + g^{2} t^{2}}$

Q. When a body is projected with velocity

\to v,

horizontally from a height

h

\begin{matrix} Column-I & Column-II (a) The speed of body at any time t is & (p) \sqrt{\frac{2 g h}{u^{2}}} (b) It will strike the ground after time t is equal to & (q) \sqrt{\frac{2 h}{g}} (c) The path followed by the body is expressed as y equal to & (r) \frac{1}{2} g \frac{x^{2}}{u^{2}} (d) The value of tan θ, where θ is the angle made by velocity striking the ground with horizontal is equal to & (s) \sqrt{v^{2} + g^{2} t^{2}} \end{matrix}

Q. An object is projected with speed

50 m/s

53^{\circ}

with horizontal from ground. The radius of curvature of its trajectory at

t = 1 sec

after projection will be:

(

g = 10 {m/s}^{2})

Q. The velocity at the maximum height of a projectile is

\frac{\sqrt{3}}{2}

times its initial velocity of projection

(u)

. Its range on the horizontal plane is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Second Law of Motion

PHYSICS

Watch in App

explore_more_icon

Explore more

Second Law of Motion

Standard IX Physics

Join BYJU'S Learning Program