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ntn ntQ. If R...

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ntn ntQ. If R & H are the horizontal range and maximum height attained by a projectile, than its speed of projection isn nt1) 2gR + 4R2/gHn nt2) 2gH + R2g/8Hn nt3) 2gH + 8H/Rgn nt4) 2gH + R2/Hn

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R

H

are the horizontal range and maximum height attained by a projectile, than its speed of projection is:

R

H

are the horizontal range and maximum height attained by a projectile , then its speed of projection is

Q. Assertion :In projectile motion if particle is projected with speed

u

, then speed of particle at height

h

\sqrt{u^{2} - 2 g h .}

Reason: If particle is projected with vertical component of velocity,

u_{y} .

Then vertical component at the height

h

\pm \sqrt{u_{y}^{2} - 2 g h .}

R

h

represent the horizontal range and maximum height respectively of an oblique projectile, then

\frac{R^{2}}{8 h} + 2 h

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