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ntWhat is the work done by 0.2 moles of a gas at room temperature to double its volume during isobaric process (Take R = 2 cal/mol^°C)?n

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Similar questions

Q. What is the work done by

0.2

mole of a gas at room temperature to double volume during isobaric process (take

R = 2 c a l m o l^{- 1} K^{- 1}

)

Q. Calculate the work done by

0.1

mole of a gas at

27^{o} C

to double its volume at constant pressure isobaric process

(R = 2 c a l m o l^{- 1} K^{- 1})

Q. Work done by

0.1 mole

27^{\circ} C

to double its volume at constant pressure is
[Take

R = 2 {cal mol}^{- 1} K^{- 1}

]

Q. Work done by

0.1 mole

27^{\circ} C

to double its volume at constant pressure is
[Take

R = 2 {cal mol}^{- 1} K^{- 1}

]

Q. Consider the cyclic process

a b c a

performed on a sample of

2

mole of an ideal gas. A total of

1000 c a l

of heat is withdrawn from the sample in the process. Find the work done by gas during the part

b c

a b

to be isobaric process and take

R = 2 c a l /^{\circ} C / m o l

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