CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Nuclear binding energy is the energy released during the hypothetical formation of the nucleus by the condensation of individual nucleons. Thus, binding energy per nucleon =Total binding energyNumber of nucleons For example, the mass of hydrogen atom is equal to the sum of the masses of a proton and an electron. For other atoms, the atomic mass is less than the sum of the masses of protons, neutrons and electrons present. This difference in mass, termed as mass defect, is a measure of the binding energy of protons and neutrons in the nucleus. The mass-energy relationship postulated by Einstein is expressed as:
ΔE=Δmc2
Where ΔE is the energy liberated, Δm is the loss of mass, and c is the speed of light.

MP and Mn are masses of a proton and a neutron respectively. For a nucleus, its binding energy is B and it contains Z protons and N neutrons, the correct relation for this nucleus if C is velocity of light is:

A
M(N,Z)=NMn+ZMpBC2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
M(N,Z)=NMn+ZMp+BC2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
M(N,Z)=NMn+ZMpBC2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
M(N,Z)=NMn+ZMp+BC2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C M(N,Z)=NMn+ZMpBC2

Mass defect= NMn+ZMpM(N,Z)

BE(Binding energy) = mass defect×C2

Given ; BE = B

BC2 = NMn+ZMp - M(N,Z)

M(N,Z) = NMn+ZMp - BC2

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Binding Energy
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon