Question

Nuclear reactor in which $U-235$ is used as fuel. Uses $2kg$ of $U-235$ in $30$ days. Then, power output of the reactor will be (given energy released per fission $=185MeV$).

• A. $43.5MW$
• B. $58.5MW$
• C. $\mathrm{69..6}MW$
• D. $73.1MW$

Answer 1

The correct option is B $58.5MW$

Number of atoms in $2kg$ of uranium
$=\frac{6.02\times {10}^{23}}{235}\times 2000$
$=5.12\times {10}^{24}$
Therefore, energy obtained from these atoms
$=5.12\times {10}^{24}\times 185MeV$
$=5.12\times {10}^{24}\times 185\times {10}^{6}eV$
Energy obtained per second
$=\frac{5.12\times {10}^{24}\times 185\times {10}^6\times 16\times {10}^{-19}}{30\times 24\times 60\times 60}$
Solving the above expression
$=58.47\times {10}^{6}W$
$\equiv 58.5MW$.