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Question

Number of atoms in 4.25 g of $$NH_3$$ is:


A
6.023×1023
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B
4×6.023×1023
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C
1.7×1024
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D
4.5×6.023×1023
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Solution

The correct option is A $$6.023 \times 10^{23}$$
Atomic mass of $$N = 14\ u$$
Atomic mass of $$H = 1\ u$$
Molar mass of $$NH_3 =14+3=17\ g/mol$$
No.of moles $$=\dfrac{4.25}{17}=0.25$$ moles
Number of molecules in 4.2 g $$NH_3 = 0.25 \times 6.022 \times 10^{23}$$
Number of atoms in one molecule of $$NH_3 = 4$$
Number of atoms in 4.2 g $$NH_3 = 4 \times 0.25 \times 6.022 \times 10^{23}$$ = $$6.022 \times 10^{23}$$

Chemistry

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