Question

# Number of atoms in 4.25 g of $$NH_3$$ is:

A
6.023×1023
B
4×6.023×1023
C
1.7×1024
D
4.5×6.023×1023

Solution

## The correct option is A $$6.023 \times 10^{23}$$Atomic mass of $$N = 14\ u$$Atomic mass of $$H = 1\ u$$Molar mass of $$NH_3 =14+3=17\ g/mol$$No.of moles $$=\dfrac{4.25}{17}=0.25$$ molesNumber of molecules in 4.2 g $$NH_3 = 0.25 \times 6.022 \times 10^{23}$$Number of atoms in one molecule of $$NH_3 = 4$$Number of atoms in 4.2 g $$NH_3 = 4 \times 0.25 \times 6.022 \times 10^{23}$$ = $$6.022 \times 10^{23}$$Chemistry

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