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Question

Number of divisors of the form (4n+2)n0 of the integer 240 is

A
4
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B
8
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C
10
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D
3
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Solution

The correct option is A 4
We can write 240 as 24.31.51
But we want divisors of the form 4n+2
That is, we want even divisors of the form 2(2n+1) and n0
The divisor is 2 (when n=0) or divisors are odd multiples of 2
So the divisors are 2, 6, 10 and 30
Hence the answer is 4

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